CAT Quantitative Aptitude Questions | CAT Ratios, Mixtures, Alligations and Averages Questions

The question is from CAT Ratio, Mixtures and Averages. What are the maximum and minimum average when some changes are made in the previous question? CAT exam is known to test on basics rather than high funda ideas. A range of CAT questions can be asked from Ratios and Proportions, Mixtures, Alligations and Averages. Make sure you master the topics. 2IIMs CAT questions bank provides you with CAT questions that can help you gear for CAT Exam CAT 2023.

Question 45: In the previous question, what can be the minimum and maximum value of A’s average if 5 teams are transferred from B to A?

1. 20.8 and 22.4
2. 20.6 and 22.6
3. 20.8 and 22.8
4. 20.8 and 21.8

Explanatory Answer

Method of solving this CAT Question from Ratio, Mixtures and Averages: How the individual data points affect the average?

For minimum, teams with minimum score would be transferred from B to A
So, total score transferred = 24 * 5 = 120
A(Minimum Average) = \\frac{(20*20 + 120)}{25}\\) = 20.8
For maximum, if we take teams with maximum score,
total score transferred = 32 * 5 = 160
However, if we assume that 5 teams scored the highest score, the average of remaining teams in B would come out to be,
\\frac{(625-160)}{20}\\) = \\frac{465}{20}\\) = 23.25 which is lower than the lowest score of B. So, 5 teams in B can’t have score of 32.
so, minimum total score which need to be on group B = 24 * 20 = 480
Score that can be transferred = 625 – 480 = 145
A(Maximum Average) = \\frac{(400 + 145)}{25}\\) = \\frac{545}{25}\\) = 21.8

The question is "In the previous question, what can be the minimum and maximum value of A’s average if 5 teams are transferred from B to A?"

Hence, the answer is "20.8 and 21.8 ".

Choice D is the correct answer.