Average of a, b, c, d and e is k, Average of b, c, d and e is also k, this implies that a = k.
If we remove b, the average drops, this implies that b is higher than the average.
e is less than k, or e is less than a. c is less than d.
e < a < b, c < d
Average of a, b, c and e is greater than average a, c, d and e. This tells us that d < b
From this, we get that b is the largest number
b - c = d - e
b + e = c + d
a + b + c + d + e = 5a
Or, b + c + d + e = 4a
b + e = 2a, c + d = 2a. Or, e, a, b is an AP, c, a, d is an AP.
e is the smallest number (as b is the largest number).
Or, the ascending order should be e c a d b
Correct Answer: Ascending order should be e, c, a, d, b
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