CAT Practice : Averages, Ratios, Mixtures

Averages

Averages

Q.44: In olympics, a game has 2 groups A and B having participants from 20 and 25 countries respectively having an average score of 20 and 25 respectively. Also,
A: Highest score: 25 Lowest score: 15
B: Highest score: 32 Lowest score: 24
What can be the minimum and maximum value of B’s average if 5 teams are transferred from A to B?

1. 25 and 25
2. 22.5 and 25
3. 23.33 and 26
4. 23.33 and 25

Choice D. 23.33 and 25

Detailed Solution

For minimum, teams with minimum score would be transferred from A to B
So, total score transferred = 15 x 5 = 75
B (Minimum Average) = $\frac{(25*25 + 75)}{30}$ = 23.33
For maximum, teams with maximum score would be transferred from A to B
So, total score transferred = 25 x 5 = 125
B (Maximum Average) = $\frac{(25*25 + 125)}{30}$ = 25

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