The question is from Permutation and Combination. Another question on counting. We need to find out the number of ways of placing toys in boxes. This section hosts a number of questions which are on par with CAT questions in difficulty on CAT Permutation and Combination, and CAT Probability.
Question 3: In how many ways 11 identical toys be placed in 3 distinct boxes such that no box is empty?
This is nothing but the number of ways of having a, b, c such that a + b + c = 11, where a, b, c are natural numbers. By having them to be natural numbers, we ensure that no box can be empty. (no zeroes)
The question is similar to the previous one. 10C2 = 45 ways
The question is "In how many ways 11 identical toys be placed in 3 distinct boxes such that no box is empty?"
Choice C is the correct answer.
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