The question is from Permutation and Combination. This question is about Sum of Rearrangements. We need to find out the sum of all possible numbers when a four digit number is rearranged. This section hosts a number of questions which are on par with CAT questions in difficulty on CAT Permutation and Combination, and CAT Probability.
Question 27: What is sum of all rearrangements of the 4-digit number 3321?
Each of the four digits is likely to appear in the units place , but the digit 3 will appear twice as that of 2 and 1.
Therefore, sum of units place = 3*2 +3*1 + 6*3 = 27.
Sum of tens place = 270
Sum of hundreds place = 2700
Sum of thousands place =27000
Sum of all arrangements of 3321 = 29997.
The question is "What is sum of all rearrangements of the 4-digit number 3321?"
Choice D is the correct answer.
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