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The question is from Permutation and Combination. This one is about rolling a die. We need to find out the the outcome of each throw being greater than the previous one. This section hosts a number of questions which are on par with CAT questions in difficulty on CAT Permutation and Combination, and CAT Probability.

Question 23: I roll a die 4 times. In how many outcomes will each subsequent throw be greater that the previous one?

  1. 15
  2. 48
  3. 30
  4. 60

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Explanatory Answer

Method of solving this CAT Question from Permutation and Combination: Outcome greater than the previous one

If we want the outcome in each throw to be greater than the previous one, essentially we are looking at four different outcomes in each throw and the possibility of each outcome being greater than the previous is possible only in one combination.
So, we are looking at just selecting four outcomes out of 6 possible outcomes when we normally roll a die. This is equal to 6C4= 15 ways.

The question is "In how many outcomes will each subsequent throw be greater that the previous one?"

Hence the answer is "15"

Choice A is the correct answer.

 


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