From the 22 points on a plane we can form ^{22}C_{3} triangles but it is given that 8 are on one straight line, 7 are on another straight line and 10 more are on another straight line, so we can form triangles on joining points which are on straight lines so we have to subtract (^{8}C_{3}+ ^{7}C_{3} +^{10}C_{3}) from the total.
Hence, we can form ^{22}C_{3} - (^{8}C_{3}+ ^{7}C_{3} +^{10}C_{3}) triangles.
Correct Answer : ^{22}C_{3} - (^{8}C_{3}+ ^{7}C_{3} +^{10}C_{3})
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