The bigger part could be any number from 1000 to 2000.
Now, if the bigger part is to be at least twice as much as the smaller part, we have
X ≥ 2Y or X ≥ 2(2000 – X)
Or X ≥ 4000/3
Given that X lies between 1000 and 2000, what is the probability that X lies between 4000/3 and 2000?
This probability is equal to (2000 − 4000/3)/(2000 − 1000) = 2/3
Answer choice (d).
Correct Answer : 2/3
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