The question is from Permutation and Combination. It is from the topic probabilty. We need to find out the probability of a particular event. This section hosts a number of questions which are on par with CAT questions in difficulty on CAT Permutation and Combination, and CAT Probability.
Question 20: A boss decides to distribute Rs. 2000 between 2 employees. He knows X deserves more that Y, but does not know how much more. So he decides to arbitrarily break Rs. 2000 into two parts and give X the bigger part. What is the chance that X gets twice as much as Y or more?
The bigger part could be any number from 1000 to 2000.
Now, if the bigger part is to be at least twice as much as the smaller part, we have
X โฅ 2Y or X โฅ 2(2000 โ X)
Or X โฅ \\frac{4000}{3}\\)
Given that X lies between 1000 and 2000, what is the probability that X lies between \\frac{4000}{3}\\) and 2000?
This probability is equal to \\frac{2000 โ 4000/3}{2000 โ 1000}\\) = \\frac{2}{3}\\)
The question is "What is the chance that X gets twice as much as Y or more?"
Choice D is the correct answer.
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