The question is from CAT Number Theory - Remainders. Given the remainder when N2 is divided by 'a', what is the remainder when N is divided by 'b'. A range of CAT questions can be asked based on Remainders. Sometimes the rigorous method works, sometimes trial and error works. In rare cases, the trial and error method is very instructive for future questions. Those questions are usually found in the 2IIM questionbank!!
Question 6: N2 leaves a remainder of 1 when divided by 24. What are the possible remainders we can get if we divide N by 12?
This again is a question that we need to solve by trial and error. Clearly, N is an odd number. So, the remainder when we divide N by 24 has to be odd.
If the remainder when we divide N by 24 = 1, then N2 also has a remainder of 1. we can also see that if the remainder when we divide N by 24 is -1, then N2 a remainder of 1.
When remainder when we divide N by 24 is ±3, then N2 has a remainder of 9.
When remainder when we divide N by 24 is ±5, then N2 has a remainder of 1.
When remainder when we divide N by 24 is ±7, then N2 has a remainder of 1.
When remainder when we divide N by 24 is ±9, then N2 has a remainder of 9.
When remainder when we divide N by 24 is ±11, then N2 has a remainder of 1.
So, the remainder when we divide N by 24 could be ±1, ±5, ±7 or ±11.
Or, the possible remainders when we divide N by 24 are 1, 5, 7, 11, 13, 17, 19, 23.
Or, the possible remainders when we divide N by 12 are 1, 5, 7, 11.
The question is "What are the possible remainders we can get if we divide N by 12?"
Choice A is the correct answer.
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