The question is from CAT Number Theory - Remainders. A large number is given and we need to find out the remainder when the number is divided by 102. A range of CAT questions can be asked based on this simple concept. When we divide 24 pigeons into 5 groups, 4 are left out or remain. This is the remainder. When there is a question based on this idea in the exam, we have a CAT among the pigeons.
Question 14: If N = (243 + 253 + 263 + 273), then N divided by 102 leaves a remainder of?
= (243 + 253 + 263 + 273)
Unit digits of N = 4 + 5 + 6 + 3 = 18
N is divisible by 2
We know that, a3 + b3 = (a + b)(a2 – ab + b2)
=> (a + b) always divides a3 + b3
Therefore, 243 + 273 is divisible by 51 (24 + 27)
Also, 253 + 263 is divisible by 51 (25 + 26)
The given divisor 102 can be expressed as 51 * 2
Hence, N is completely divisible by 102
Remainder = 0
The question is "If N = (243 + 253 + 263 + 273), then N divided by 102 leaves a remainder of?"
Choice D is the correct answer.
CAT® (Common Admission Test) is a registered trademark of the Indian Institutes of Management. This website is not endorsed or approved by IIMs.
2IIM Online CAT Coaching
A Fermat Education Initiative,
10-C, Kalinga Colony, Bobbili Raja Salai
K.K.Nagar, Chennai. India. Pin - 600 078