The question is about a particular term of a Geometric Progression. Sum of two terms in A GP is equal to zero, what we can infer from this. With some simple but very powerful ideas, one can cut down on a lot of working when it comes to progressions. For example, anchoring a progression around its middle term can be very useful. CAT Exam tests the idea of progression often in the CAT Quantitative Aptitude section and this could also be tested in DI LR section of the CAT Exam as a part of a puzzle.

Question 2: Sum of first 12 terms of a GP is equal to the sum of the first 14 terms in the same GP. Sum of the first 17 terms is 92, what is the third term in the GP?

- 92
- -92
- 46
- 231

92

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Sum of first 12 terms is equal to sum of first 14 terms.

Sum of first 14 terms = Sum of first 12 terms + 13^{th} term + 14^{th} term

=> 13^{th} term + 14^{th} term = 0

Let us assume 13^{th} term = k, common ratio = r. 14^{th} term will be kr.

k + kr = 0

k (1 + r) = 0

=> r = -1 as k cannot be zero

Common ratio = -1.

Now, if the first term of this GP is a, second term would be -a, third would be a and so on

The GP would be a, -a, a, -a, a, -a,...

Sum to even number of terms = 0

Sum to odd number of terms = a

Sum to 17 terms is 92 => a = 92

Third term = a = 92

The question is **"what is the third term in the GP?"**

Choice A is the correct answer.

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