CAT Quantitative Aptitude Questions | CAT Time and Work questions

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CAT Quantitative Aptitude
Pipes,Cisterns; Work,Time ▽

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HCF and LCM Factors Remainders Factorials Digits Ratios,Mixtures;Averages Percents; Profits; SICI Speed & Time; Races Logarithms and Exponents Set Theory Geometry Coordinate Geometry Mensuration Trigonometry Linear & Quadratic Equations Functions Inequalities Polynomials Progressions Permutation Probability
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Explanatory Answer

Method of solving this CAT Question from Pipes Cisterns and Work Time: Finding one answer is usually far easier than finding "boundary conditions". But this boundary condition thing can be very instructive.

4m and 6w finish in 24 days.
In one day, 4m + 6w = \\frac{1}{24}\\) of task.
In these questions, just substitute extreme values to get the whole range
If a woman is half as efficient as man
4m + 3m = \\frac{1}{24}\\), 7m = \\frac{1}{24}\\), m = \\frac{1}{168}\\)
6w + 2m = 3m + 2m = 5m, 5m will take \\frac{168}{5}\\) days = 33.6 days
If a woman is as efficient as a man
4m + 6w finish in 24 days
10m finish \\frac{1}{24}\\) of task in a day
6w + 2m = 8m, 8m will take \\frac{240}{8}\\) = 30 days to finish the task.
So, the range = 30 to 33.6 days. The new team will take 30 to 33.6 days to finish the task.

The question is "what is the range of the number of days for 6 women and 2 men to complete the same task?"

Hence, the answer is "30 to 33.6 days".

Choice A is the correct answer.