The question is from CAT Coordinate Geometry. This is about area under curve. We need to find out the area of the region which is enclosed by given lines. Take Geometry, add one unit of algebra; take a diagram, explain it with x's and y's. For the purists, it is geometry without the romance, for the pragmatists it is Geometry with expanded scope. It is important to cover ideas from Coordinate Geometry in your CAT Preparation
Question 5: What is the area enclosed in the region defined by y = |x โ 1| + 2, line x = 1, Xโaxis and Yโaxis?
Let us first draw y = |x|.
Now, y = |x โ 1| is just a shift of โ1โ unit to the right along the xโaxis.
Now, y = |x โ 1| + 2 is a shift of โ2โ units to the top along the yโaxis.
Now, let us complete the diagram by drawing the line x = 1 also.
The required area is essentially the area of the shaded region.
The point of intersection of y = |x โ 1| + 2 where the yโaxis can be found by substituting x = 0 in the equation.
Thus we get y = 3.
Required area = Area of the trapezium formed by the points (0, 0), (1, 0), (1, 2) and (0, 3).
Area of a trapezium = \\frac{1}{2}\\) * height * sum of the parallel sides = \\frac{1}{2}\\) * 1 * (3 + 2) = \\frac{5}{2}\\) sq units.
The question is "What is the area enclosed in the region defined by y = |x โ 1| + 2, line x = 1, Xโaxis and Yโaxis?"
Choice B is the correct answer.
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