Any point on the line = 1 will have the shortest overall distance. However, we need to have integral coordinates. So, we need to find points with integral coordinates as close as possible to the line 5x + 3y = 15.
Substitute x =1, we get y = 2 or 3
Substitute x = 2, we get y = 1 or 2
Sum of distances for (1, 2) =
Sum of distances for (1, 3) =
Sum of distances for (2, 1) =
Sum of distances for (2, 2) =
is the shortest distance.
Sum of abscissa + ordinate = 4
Correct Answer: 4
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