The question is from Log and Exponents. We can solve this easily using log identities. We need to find out the value of x from the given equation. With every extra hour you log in for this topic, it becomes exponentially simpler. CAT Logarithms and Exponents is a favorite in CAT Exam, and appears more often than expected in the CAT Quantitative Aptitude section in the CAT Exam
Question 7: log3x + logx3 = 174. Find the value of x.
log3x + logx3 = 174
Let y = log3x
We know that logx3 = 1log3x
Hence logx3 = 1y
Thus the equation can be written as y + 1y = 174
4y2 + 4 = 17y
4y2 + 4 - 17y = 0
Solving the above equation we get y = 4 or 14
If y = 4
log3x = 4
Then x = 34
If y = 14
log3x = 14
Then x = 31/4
The question is "Find the value of x."
Choice C is the correct answer.
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