x^{2} - |x + 3| + x > 0
If x + 3 > 0 x > -3
Then equation is in the form x^{2} - x - 3+ x > 0 i.e., x^{2} -3 > 0
x^{2} > 3 and
But x > -3, thus x >
Now if x + 3 < 0 x < -3
Then equation is in the form x^{2} + x + 3 + x > 0 x^{2} + 2x + 3 > 0
Discriminant < 0 a > 0 and iequality > 0 exist for all value of x.
But x < -3 , thus range will be x < -3
Combining both x
Correct Answer: x
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