The last two digits of 7^{1} are 07.
The last two digits of 7^{2} are 49.
The last two digits of 7^{3} are 43.
The last two digits of 7^{4} are 01.
The last two digits of powers of 7 go in a cycle - 07, 49, 43, 01.
So, the last two digits of 7^{45} are 07.
Correct Answer: 07
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