The question is about basic factorial. We need to find out the possible values of 'n', when n! is a multiple of ax but not ay. Dealing with factorials of a number is a vital component in CAT Number Theory. Dealing with factorials of a number is a vital component in CAT Number Theory in the CAT Exam. A range of CAT questions can be asked based on this simple concept in the CAT exam. Factorials are also useful in Permutation Combination questions in CAT. Make use of 2IIMs Free CAT Questions, provided with detailed solutions and Video explanations to obtain a wonderful CAT score. If you would like to take these questions as a Quiz,head on here to take these questions in a test format, absolutely free.
Question 3: How many values can natural number n take, if n! is a multiple of 76 but not 79?
The smallest factorial that will be a multiple of 7 is 7!
14! will be a multiple of 72
Extending this logic, 42! will be a multiple of 76
However, 49! will be a multiple of 78 as 49 (7 * 7) will contribute two 7s to the factorial. (This is a standard question whenever factorials are discussed). Extending beyond this, 56! will be a multiple of 79.
In general for any natural number n,
n! will be a multiple of [\\frac{n}{7}\\)] + [\\frac{n}{49}\\)] + [\\frac{n}{343}\\)] + ...........
where [x] is the greatest integer less than or equal to x.
So, we see than 42! is a multiple of 76. We also see that 56! is the smallest factorial that is a multiple of 79. So, n can take values {42, 43, 44, 45........55}
There are 14 values that n can take.
The question is "How many values can natural number n take, if n! is a multiple of 76 but not 79?"
Choice C is the correct answer.
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