The question is from CAT Geometry - Triangles. It discusses about the circles inscribed in the equilateral triangle. CAT Geometry questions are heavily tested in CAT exam. Make sure you master Geometry problems. With the given diagram how could we find the ratio of the inscribed circle to the equilateral triangle
Question 4: Two circles are placed in an equilateral triangle as shown in the figure. What is the ratio of the area of the smaller circle to that of the equilateral triangle
In-radius of equilateral triangle of side a = \\frac{a}{2√3}\\)
Diameter of larger circle = \\frac{a}{2√3}\\)
Let us say common tangent PQ touches the two circle at R, center of smaller circle is I.
Now, PQ is parallel to BC. AR is perpendicular to PQ. Triangle PQR is also an equilateral triangle and AORID is a straight line. (Try to establish each of these observations. Just to maintain the rigour.)
AD = \\frac{√3}{2}\\)a
RD = \\frac{a}{√3}\\)
AR = \\frac{√3}{2}\\)a - \\frac{a}{√3}\\) = \\frac{3a-2a}{2√3}\\) = \\frac{a}{2√3}\\)
AR = \\frac{1}{3}\\) AD
Radius of smaller circle = \\frac{1}{3}\\) radius of larger circle
Radius of smaller circle = \\frac{1}{3}\\) * \\frac{a}{2√3}\\) = \\frac{a}{6√3}\\)
Area of smaller circle = πr2
π (\\frac{a}{6√3}\\))2 = \\frac{πa^2}{108}\\)
Area of triangle = \\frac{√3}{4}\\)a2
Ratio = \\frac{πa^2}{108}\\) : \\frac{√3}{4}\\)a2 = π:27√3
The question is " What is the ratio of the area of the smaller circle to that of the equilateral triangle?"
Choice C is the correct answer.
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