When t = 7, f(x) = |x| + |x+3| + |x+6| + ……………………………..+ |x+21| This expression has two middle terms: |x+9|, |x+12| The value of f(x) will be minimized when the sum of the two middle terms are minimized =) |x+9|+ |x+12| should be minimum This happens when -12 ≤ x ≤ -9, Note that for x = -12, -11, -10, -9 the value of the sum of the middle terms = 3. Therefore, for all 4 values of x, f(x) will have minimum value. Answer choice (C). Correct Answer: 4
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