CAT Practice : Averages, Ratios, Mixtures

Averages

Averages

    Q.45: In the previous question, what can be the minimum and maximum value of A’s average if 5 teams are transferred from B to A?
    1. 20.8 and 22.4
    2. 20.6 and 22.6
    3. 20.8 and 22.8
    4. 20.8 and 21.8

 

  • Correct Answer
    Choice D. 20.8 and 21.8

Detailed Solution

For minimum, teams with minimum score would be transferred from B to A
So, total score transferred = 24 x 5 = 120
A(Minimum Average) = = 20.8
For maximum, if we take teams with maximum score,
total score transferred = 32 x 5 = 160
However, if we assume that 5 teams scored the highest score, the average of remaining teams in B would come out to be,
which is lower than the lowest score of B. So, 5 teams in B can’t have score of 32.
so, minimum total score which need to be on group B = 24 x 20 = 480
Score that can be transferred = 625 – 480 = 145
A(Maximum Average) =







Correct Answer: 20.8 and 21.8



Our Online Course, Now on Google Playstore!

2IIM's App

Fully Functional Course on Mobile

All features of the online course, including the classes, discussion board, quizes and more, on a mobile platform.


Cache Content for Offline Viewing

Download videos onto your mobile so you can learn on the fly, even when the network gets choppy!

Get it on Google Play
Visit Piverb.com
Visit Wizako.com