# CAT Practice : Averages, Ratios, Mixtures

Averages

## Averages

Q.44: In olympics, a game has 2 groups A and B having participants from 20 and 25 countries respectively having an average score of 20 and 25 respectively. Also,
A: Highest score: 25 Lowest score: 15
B: Highest score: 32 Lowest score: 24
What can be the minimum and maximum value of B’s average if 5 teams are transferred from A to B?

1. 25 and 25
2. 22.5 and 25
3. 23.33 and 26
4. 23.33 and 25

• Correct Answer
Choice D. 23.33 and 25

## Detailed Solution

For minimum, teams with minimum score would be transferred from A to B
So, total score transferred = 15 x 5 = 75
B (Minimum Average) = $\frac{(25*25 + 75)}{30}$ = 23.33
For maximum, teams with maximum score would be transferred from A to B
So, total score transferred = 25 x 5 = 125
B (Maximum Average) = $\frac{(25*25 + 125)}{30}$ = 25

Correct Answer: 23.33 and 25

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