Questionbank: Permutation and Probability

This is more a puzzle than a challenging question. But is a very interesting puzzle nevertheless :)

Permutation Combination Puzzle

    Q.4: a, b, c are three distinct integers from 2 to 10 (both inclusive). Exactly one of ab, bc and ca is odd. abc is a multiple of 4. The arithmetic mean of a and b is an integer and so is the arithmetic mean of a, b and c. How many such triplets are possible (unordered triplets)?
    1. 8
    2. 6
    3. 2
    4. 4

 

  • Correct Answer
    Choice D. 4

Detailed Solution

Exactly one of ab, bc and ca is odd => Two are odd and one is even

abc is a multiple of 4 => the even number is a multiple of 4

The arithmetic mean of a and b is an integer => a and b are odd

and so is the arithmetic mean of a, b and c. => a+ b + c is a multiple of 3

c can be 4 or 8.
c = 4; a, b can be 3, 5 or 5, 9
c = 8; a, b can be 3, 7 or 7, 9

Four triplets are possible.

Correct Answer : 4

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