CAT Practice : Pipes cisterns, Work time

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A simple Work and Time question that makes you think !!

Pipes Cisterns - Work Time

    Q.8: B takes 12 more days than A to finish a task. B and A start this task and A leaves the task 12 days before the task is finished. B completes 60% of the overall task. How long would B have taken to finish the task if he had worked independently?
    1. 48 days
    2. 36 days
    3. 28 days
    4. 32 days

 

  • Correct Answer
    Choice B. 36 days

Explanatory Answer

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Detailed Solution

Let us say A and B split their share of the task and started doing their respective shares simultaneously.

Let’s say A takes A days to finish the task. Therefore, B takes A + 12 days to finish the entire task.

A has to finish 40% of the task, since B is doing the rest. So A will only take 2A/5 number of days.

B only has to finish 60% of the task, so B will take number of days.

But as we know, B starts working along with A and finishes 12 days after A stops working.

So, =

3A + 36 = 2A + 60

A = 24; B = 36 days.

Answer choice (b)

Correct Answer: 36 days



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Mathematicians are creatures of habit. This topic has been called Pipes and Cisterns because someone named it like it long ago. Pipes and Tanks would be much better - at least makes it sound like wartime.