# CAT Practice : Percents, Profits

Three Wokers

## Burger Competition

Q.33: A, B and C participated in a burger eating competition. A beat C by 18 burgers. A also beat B by eating 50% more burger than B. Also B had eaten 5 percentage points more burger than C. Find the overall number if burgers that were eaten.
1. 90 burgers
2. 81 burgers
3. 72 burgers
4. 100 burgers

Choice A. 90 burgers

## Detailed Solution

Let the burgers eaten by C be x%

= ) Burgers eaten by B = x + 5%

Since A ate 50% more than B = (x + 5%) + 50% of (x+5%) = 1.5 (x+5%)

= ) x + x + 5 + 1.5(x+ 5) = 100%

= ) x = $\frac{87.5}{3.5} = 25% = )C - 25%, B – 30%, A – 45%$

Therefore, A beat C by 20 percentage points = ) 18 = ) Total burger = $18 * \frac{100}{20} = 90$

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## More questions from Averages, Ratios, Mixtures

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