h(x) = g(f(x)) = g(x2 + 2x) = = |x + 1| This bit is very important, and often overlooked. = 3, not ±3 If x2 = 9, then x can be ±3, but is only +3. So, = |x|, not +x, not ±x Domain of |x + 1| = ( -∞, +∞), x can take any value. As far as the range is concerned, |x + 1| cannot be negative. So, range = [0, ∞) Correct Answer: Domain: ( -∞, +∞), Range -[0, ∞]
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