This question requires a good deal of visualization. Since, both the box and cans are hard solids, simply dividing the volume won’t work because the shape can’t be deformed.
Each cylindrical can has a diameter of 14 cm and while they are kept erect in the box will occupy height of 30 cm
Number of such cans that can be placed in a row = = 5 (Remaining space will be vacant)
Number of such rows that can be placed =
Thus 5 x 3 = 15 cans can be placed in an erect position.
However, height of box = 45cm and only 30 cm has been utilized so far
Remaining height = 15 cm > 14 cm (Diameter of the can)
So, some cans can be placed horizontally on the base.
Number of cans in horizontal row =
Number of such rows =
∴ 2 x 3 = 6 cans can be placed horizontally
∴ Maximum number of cans = 15+6 = 21
Choice (D) is therefore, the correct answer.
Correct Answer: 21